Int32.TryParse Method

                             Int32.TryParse Method has 2 overload  list

     TryParse(String, Int32)
       TryParse(String, NumberStyles, IFormatProvider, Int32) 

 private static void TryToParse(string value)
   {
      int number;
      bool result = Int32.TryParse(value, out number);
      if (result)
      {
         Console.WriteLine("Converted '{0}' to {1}.", value, number);        
      }
      else
      {
         if (value == null) value = "";
         Console.WriteLine("Attempted conversion of '{0}' failed.", value);
      }
   }
string numericString;
      NumberStyles styles;
      numericString = "106779";
      styles = NumberStyles.Integer;
      CallTryParse(numericString, styles);
 private static void CallTryParse(string stringToConvert, NumberStyles styles)
   {
      int number;
      CultureInfo provider;
      // If currency symbol is allowed, use en-US culture.
      if ((styles & NumberStyles.AllowCurrencySymbol) > 0)
         provider = new CultureInfo("en-US");
      else
         provider = CultureInfo.InvariantCulture;
      bool result = Int32.TryParse(stringToConvert, styles,
                                   provider, out number);
      if (result)
         Console.WriteLine("Converted '{0}' to {1}.", stringToConvert, number);
      else
         Console.WriteLine("Attempted conversion of '{0}' failed.",
                           Convert.ToString(stringToConvert));
   }